0²=0
1²=1
2²=4
3²=9
4 ²=16
5²=25
6²=36
7²=49
8²=64
9²=81
10²=100
11²=121
12²=144
13²=169
14²= 196
15²= 225
Observe the pattern,the las digits of perfect squares are 0,1,4,9,6,5,6,9,4,1,0 and back again to 1-0.Therefore,we have now a one digit clue in reciting perfect squares.
And for our Remaining digits the pattern is...
For first 3,0 is excluded,n² the first digit is 0
the 4²,5²,6²,7² have 1 adjacent difference on their 1st digit
49,36,25,16
4-3=1
3-2=1
2-1=1
It means every remaining digits are will be added to 1
BUT the excemption is the pattern will change in every n that the last digit is 3 and 7.
1²=01 the first pattern is to add 0 in every remaining digits[n/a:the 0 on first digit just only a guide]Just follow the pattern on every last digits.(1,4,9,6,5,6,9,4,1,0...)
2²=04
3²=09 the n is 3.Therefore,the pattern will change by adding 1 on the remaining digits
4²=16
5²=25
6²=36
7²=49 The n is 7.Therefore,the pattern will change by adding 2 on the remaining digits
8²=64
9²=81
10²=100 Explain.8+2=10
11²=121
12²=144
13²=169
And so on.
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My Mathematical Theories
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