A... Non-Business Meeting?

3.8K 135 509
                                    

Peter
Ned. It's time. For class.

And I'm not letting you join the chat

Ned
Why not?!?

Peter
Because you'll just hack into his phone!

Ned
*sad sigh*

Peter
Smh

Ned
Pleeeeeease

Peter
No.

Ned
Finnnnne

>>>You are now texting Dr. Ruffalo and Coffee Einstein<<<

Parker
Hello!!

Dr. Ruffalo
Good afternoon Mr. Parker

Coffee Einstein
Sup kid

Dr. Ruffalo
Aren't you in a meeting?

Coffee Einstein
Not an important one

Dr. Ruffalo
Kind of important

Parker
A business meeting?

Coffee Einstein
More like a... non-business meeting

Parker
CoOl

Coffee Einstein
(;

Parker
:D

Dr. Ruffalo
Back on topic please

Parker
Sorry

Dr. Ruffalo
I believe I said we're starting Electrostatic Problems today, correct?

Parker
Yup!

Dr. Ruffalo
Alright. I'll walk you through the first one, then see if you can answer the rest on your own

Sound good?

Parker
Yup

Dr. Ruffalo
Great

Two identical objects, separated by a distance d, with charges equal in magnitude but of opposite signs exert a force of attraction of - 2.5 N on each other. What force do these objects exert on each other if the distance between them becomes 2d?

Let the two charges be q and -q. The magnitude of the force that q and -q, separated by a distance d, exert on each other is given by which law?

Parker
Coulomb's law

Dr. Ruffalo
Which is?

Parker
F = k (q) (- q) / d2 = - k q2 / d2 = - 2.5 N

Dr. Ruffalo
Correct.

So the magnitude of the force F2 that q and -q, separated by a distance 2 d, exert on each other is given by Coulomb's law, which would equal

Coffee Einstein
F2 = k (q) (- q) / (2 d)2 = - k q2 / 4 d2 = F / 4 = - 2.5 / 4 = - 0.625 N

Dr. Ruffalo
...

It Was Only Supposed to be an Online Class...Where stories live. Discover now